For ax2 + bx + c = 0,
x = [-b ± √(b2 - 4ac)] / 2a
This works for all quadratics.
2x2 + 5x - 3 = 0
a=2, b=5, c=-3
x = [-5 ± √(25 - 4×2×-3)] / 4 = [-5 ± √49] / 4 = [-5 ± 7] / 4
x = 1/2 or x = -3
Δ > 0: Two distinct real roots
Δ = 0: One repeated real root
Δ < 0: No real roots
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1. Solve using the formula: x2 - 4x + 1 = 0. Give answers to 2 d.p.2. Solve: 3x2 + …
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