If ax = b, then logab = x.
We say: log base a of b equals x. (a is the base, b is the argument.)
23 = 8 ⇒ log28 = 3
102 = 100 ⇒ log10100 = 2
50 = 1 ⇒ log51 = 0
logaa = 1 (because a1 = a)
loga1 = 0 (because a0 = 1)
Note: The base a > 0 and a ≠ 1. The argument b > 0.
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Write in log form:34 = 81103 = 100071 = 7Write in index form:log232 = 5log100.01 = -2log464 = 3
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